1"use strict";(self.webpackChunk_N_E=self.webpackChunk_N_E||[]).push([[2523],{52523:(e,t,r)=>{r.r(t),r.d(t,{default:()=>u});var l,n,a=r(14232),i=["title","titleId"];function o(){return(o=Object.assign?Object.assign.bind():function(e){for(var t=1;t<arguments.length;t++){var r=arguments[t];for(var l in r)({}).hasOwnProperty.call(r,l)&&(e[l]=r[l])}return e}).apply(null,arguments)}let u=function(e){var t=e.title,r=e.titleId,u=function(e,t){if(null==e)return{};var r,l,n=function(e,t){if(null==e)return{};var r={};for(var l in e)if(({}).hasOwnProperty.call(e,l)){if(-1!==t.indexOf(l))continue;r[l]=e[l]}return r}(e,t);if(Object.getOwnPropertySymbols){var a=Object.getOwnPropertySymbols(e);for(l=0;l<a.length;l++)r=a[l],-1===t.indexOf(r)&&({}).propertyIsEnumerable.call(e,r)&&(n[r]=e[r])}return n}(e,i);return a.createElement("svg",o({xmlns:"http://www.w3.org/2000/svg",width:"1em",height:"1em",fill:"none",viewBox:"0 0 24 24","aria-labelledby":r},u),t?a.createElement("title",{id:r},t):null,l||(l=a.createElement("path",{fill:"currentColor",stroke:"currentColor",strokeWidth:.167,d:"M13.342 5.41a.42.42 0 0 1 .433-.03v-.001a.42.42 0 0 1 .222.314l.004.058V17.75a.42.42 0 0 1-.177.34l-.05.03a.415.415 0 0 1-.432-.032l-4.535-3.24-.022-.014h-3.2a.417.417 0 0 1-.417-.417V9.084c0-.23.186-.417.417-.417h3.198l.022-.016zm-.306 1.246L9.37 9.274l-.035.026v4.903l.035.025 3.666 2.618.048-.066h.084V6.562zM6.002 14h2.5V9.5h-2.5zM15.05 8.862a.416.416 0 0 1 .589 0l.02.02a4.086 4.086 0 0 1-.02 5.754.414.414 0 0 1-.524.054l-.065-.054a.416.416 0 0 1 0-.59 3.253 3.253 0 0 0 0-4.595.416.416 0 0 1 0-.589Z"})),n||(n=a.createElement("path",{fill:"currentColor",stroke:"currentColor",strokeWidth:.167,d:"M16.469 7.442a.416.416 0 0 1 .584.005 6.09 6.09 0 0 1 0 8.604h-.001a.413.413 0 0 1-.589 0 .416.416 0 0 1 0-.59 5.254 5.254 0 0 0 0-7.423.416.416 0 0 1 0-.589z"})))}}}]);
Line numbers count LF bytes from the start of the resource, as the search results do. Vendor segments are library code the classifier recognised; they are stored but not indexed. Bytes are shown as Latin1 characters, one per byte.