https://www.visitmorocco.com/sites/all/modules/contrib/admin_menu/admin_devel/admin_devel.js?te0fya

1(function($) {
2
3/**
4 * jQuery debugging helper.
5 *
6 * Invented for Dreditor.
7 *
8 * @usage
9 *   $.debug(var [, name]);
10 *   $variable.debug( [name] );
11 */
12jQuery.extend({
13  debug: function () {
14    // Setup debug storage in global window. We want to look into it.
15    window.debug = window.debug || [];
16
17    args = jQuery.makeArray(arguments);
18    // Determine data source; this is an object for $variable.debug().
19    // Also determine the identifier to store data with.
20    if (typeof this == 'object') {
21      var name = (args.length ? args[0] : window.debug.length);
22      var data = this;
23    }
24    else {
25      var name = (args.length > 1 ? args.pop() : window.debug.length);
26      var data = args[0];
27    }
28    // Store data.
29    window.debug[name] = data;
30    // Dump data into Firebug console.
31    if (typeof console != 'undefined') {
32      console.log(name, data);
33    }
34    return this;
35  }
36});
37// @todo Is this the right way?
38jQuery.fn.debug = jQuery.debug;
39
40})(jQuery);