https://arahr.com/_next/static/chunks/pages/amps-to-watts-58e644f535f1dc7d.js

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1),(0,r.jsx)("p",{children:"1. Volts (V) = 120V, Amps (A) = 5A"}),(0,r.jsx)("p",{children:"Watts (W) = V x A"}),(0,r.jsx)("p",{children:"W = 120V x 5A = 600W"}),(0,r.jsx)("p",{children:"2. V = 240V, A = 2A"}),(0,r.jsx)("p",{children:"W = 240V x 2A = 480W"}),(0,r.jsx)("p",{children:"3. V = 12V, A = 10A"}),(0,r.jsx)("p",{children:"W = 12V x 10A = 120W"}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsx)("h3",{children:"How Many Watts Are in an Amp?"}),(0,r.jsxs)("p",{className:"lead text-dark",children:["The number of watts in an amp depends on the voltage. ",(0,r.jsx)("br",{})," Watts (W) are a unit of power, while amps (A) are a unit of current. ",(0,r.jsx)("br",{})," To find the watts, you need to know the voltage (V) and the current (I)."]}),(0,r.jsx)("p",{children:"The formula is:"}),(0,r.jsx)("p",{children:(0,r.jsx)("strong",{children:(0,r.jsx)("mark",{children:"W = V x I"})})}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsxs)("p",{children:[(0,r.jsx)("em",{children:"Examples"}),":"]}),(0,r.jsx)("p",{children:"1. If you have 1 amp of current at 120 volts, the power would be:"}),(0,r.jsx)("p",{children:"W = 120V x 1A = 120W"}),(0,r.jsxs)("p",{children:[(0,r.jsx)("br",{}),"2. If we have 5 amps of current at 120 volts, then the power will be"]}),(0,r.jsx)("p",{children:"W= 120V x 5A = 600W."}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsx)("h3",{children:"What is the Conversion for Single-Phase AC Circuits?"}),(0,r.jsx)("p",{children:"For single-phase AC circuits, the power formula is: "}),(0,r.jsx)("p",{children:(0,r.jsx)("strong",{children:(0,r.jsx)("mark",{children:"P = V \xd7 I \xd7 cos(φ)"})})}),(0,r.jsx)("p",{children:"Where: "}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"P"})," = Power in watts"]}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"V"})," = Voltage in volts"]}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"I"})," = Current in amps"]}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"cos(φ)"})," = Power factor (typically 0.8-1.0)"]}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsx)("h4",{children:"Typical power factor values"}),(0,r.jsx)("table",{className:"table table-bordered table-sm",children:(0,r.jsxs)("tbody",{children:[(0,r.jsxs)("tr",{children:[(0,r.jsx)("td",{children:(0,r.jsx)("p",{className:"fw-bolder",children:"Device"})}),(0,r.jsx)("td",{children:(0,r.jsx)("p",{className:"fw-bolder",children:"Typical power factor"})})]}),(0,r.jsxs)("tr",{children:[(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"Resistive load"})}),(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"1"})})]}),(0,r.jsxs)("tr",{children:[(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"Fluorescent lamp"})}),(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"0.95"})})]}),(0,r.jsxs)("tr",{children:[(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"Incandescent lamp"})}),(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"1"})})]}),(0,r.jsxs)("tr",{children:[(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"Induction motor full load"})}),(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"0.85"})})]}),(0,r.jsxs)("tr",{children:[(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"Induction motor no load"})}),(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"0.35"})})]}),(0,r.jsxs)("tr",{children:[(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"Resistive oven"})}),(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"1"})})]}),(0,r.jsxs)("tr",{children:[(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"Synchronous motor"})}),(0,r.jsx)("td",{children:(0,r.jsx)("p",{children:"0.9"})})]})]})}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsx)("p",{children:"For resistive loads (power factor = 1):"}),(0,r.jsx)("p",{children:(0,r.jsx)("strong",{children:(0,r.jsx)("mark",{children:"P = V \xd7 I"})})}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsxs)("p",{children:[(0,r.jsx)("em",{children:"Example"}),(0,r.jsx)("strong",{children:":"})]}),(0,r.jsx)("p",{children:"10A at 230V with PF = 0.9, then we have the following power:"}),(0,r.jsx)("p",{children:"W = 10 x 230 x 0.9 = 2070W ."}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsx)("h3",{children:"What is the Conversion for Three-Phase AC Circuits?"}

1),(0,r.jsx)("p",{children:"For three-phase AC circuits, there are two formulas:"}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"Using Line-to-Line Voltage"}),":"]}),(0,r.jsx)("p",{children:(0,r.jsx)("strong",{children:(0,r.jsx)("mark",{children:"W = √3 x VL x I \xd7 cos(φ)"})})}),(0,r.jsx)("p",{children:"Where:"}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"W"})," = power in watts (W)"]}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"VL"})," = line-to-line voltage in volts (V)"]}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"I"})," = current in amps (A)"]}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"cos(φ) "}),"= power factor"]}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsxs)("p",{children:[(0,r.jsx)("em",{children:"Example"}),":"]}),(0,r.jsx)("p",{children:"10A, 400V (line-to-line), PF = 0.85"}),(0,r.jsx)("p",{children:"W = √3 x 10 X 400 x 0.85 ≈ 5896W"}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"Using Line-to-Neutral Voltage"}),":"]}),(0,r.jsx)("p",{children:(0,r.jsx)("strong",{children:(0,r.jsx)("mark",{children:"W = 3 x V x I \xd7 cos(φ)"})})}),(0,r.jsx)("p",{children:"Where:"}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"W"})," = power in watts (W)"]}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"VLN"})," = line-to-neutral voltage in volts (V)"]}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"I"})," = current in amps (A)"]}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"cos(φ) "}),"= power factor"]}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsx)("p",{children:"Note: VL = √3 \xd7 VLN, so both formulas are equivalent."}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsxs)("p",{children:[(0,r.jsx)("em",{children:(0,r.jsx)("strong",{children:"Example"})}),":",(0,r.jsx)("br",{})," 10A, 230V (line-to-neutral), PF = 0.85",(0,r.jsx)("br",{})," W = 3 x 10 x 230 x 0.85 = 5865W."]}),(0,r.jsx)("br",{}),(0,r.jsx)("h3",{children:"How to Convert Amps and Ohms to Watts?"}),(0,r.jsxs)("p",{children:["You need to know the voltage to convert amps and ohms to watts. ",(0,r.jsx)("br",{})," ",(0,r.jsx)("br",{})," You can use Ohm's Law to find the voltage:"]}),(0,r.jsx)("p",{children:(0,r.jsx)("strong",{children:(0,r.jsx)("mark",{children:"V = I x R."})})}),(0,r.jsx)("p",{children:"Where:"}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"V"})," = voltage in volts (V)"]}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"I"})," = current in amps (A)"]}),(0,r.jsxs)("p",{children:[(0,r.jsx)("strong",{children:"R"})," = resistance in ohms (Ω)"]}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsx)("p",{children:"Then, you can use the formula:"}),(0,r.jsx)("p",{children:"W = V x I or"}),(0,r.jsx)("p",{children:"W = I\xb2 \xd7 R or"}),(0,r.jsx)("p",{children:"W = V\xb2/R"}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsxs)("p",{children:[(0,r.jsx)("em",{children:"Example"}),":"]}),(0,r.jsxs)("p",{children:["5A through a 10Ω resistor",(0,r.jsx)("br",{})," W = 5\xb2 x 10 = 250W."]}),(0,r.jsx)("p",{children:"\xa0"}),(0,r.jsx)("h3",{children:"What are Amps, Volts, and Watts?"}),(0,r.jsx)("p",{children:"Amps, volts, and watts are units of measurement for electricity:"}),(0,r.jsxs)("ul",{children:[(0,r.jsxs)("li",{children:[(0,r.jsx)("strong",{children:"Volts (V)"}),': Electric potential difference or "pressure" that pushes electrons through a circuit. 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